Using Assumptions
Mathematica normally makes as few assumptions as possible about the objects you ask it to manipulate. This means that the results it gives are as general as possible. But sometimes these results are considerably more complicated than they would be if more assumptions were made.
| Refine[expr,assum] | refine expr using assumptions |
| Simplify[expr,assum] | simplify with assumptions |
| FullSimplify[expr,assum] | full simplify with assumptions |
| FunctionExpand[expr,assum] | function expand with assumptions |
Doing operations with assumptions.
Simplify by default does essentially nothing with this expression.
| Out[1]= |  |
The reason is that its value is quite different for different choices of
x.
| Out[2]= |  |
With the assumption

,
Simplify can immediately reduce the expression to 0.
| Out[3]= |  |
Without making assumptions about
x and
y, nothing can be done.
| Out[4]= |  |
If
x and
y are both assumed positive, the log can be expanded.
| Out[5]= |  |
By applying
Simplify and
FullSimplify with appropriate assumptions to equations and inequalities, you can in effect establish a vast range of theorems.
Without making assumptions about
x, the truth or falsity of this equation cannot be determined.
| Out[6]= |  |
Now
Simplify can prove that the equation is true.
| Out[7]= |  |
This establishes the standard result that the arithmetic mean is larger than the geometric one.
| Out[8]= |  |
This proves that

lies in the range

for all positive arguments.
| Out[9]= |  |
Simplify and
FullSimplify always try to find the simplest forms of expressions. Sometimes, however, you may just want
Mathematica to follow its ordinary evaluation process, but with certain assumptions made. You can do this using
Refine. The way it works is that
Refine
performs the same transformations as
Mathematica would perform automatically if the variables in
expr were replaced by numerical expressions satisfying the assumptions
assum.
There is no simpler form that
Simplify can find.
| Out[10]= |  |
Refine just evaluates
Log
as it would for any explicit negative number

.
| Out[11]= |  |
An important class of assumptions is those which assert that some object is an element of a particular domain. You can set up such assumptions using

, where the

character can be entered as

or
\[Element].
x dom or Element[x,dom] | assert that x is an element of the domain dom |
{x1,x2,...} dom | assert that all the are elements of the domain dom |
patt dom | assert that any expression which matches patt is an element of the domain dom |
Asserting that objects are elements of domains.
This confirms that

is an element of the domain of real numbers.
| Out[12]= |  |
These numbers are all elements of the domain of algebraic numbers.
| Out[13]= |  |
Mathematica knows that

is not an algebraic number.
| Out[14]= |  |
Current mathematics has not established whether

is an algebraic number or not.
| Out[15]= |  |
This represents the assertion that the symbol

is an element of the domain of real numbers.
| Out[16]= |  |
Domains supported by Mathematica.
If

is assumed to be an integer,

is zero.
| Out[17]= |  |
This establishes the theorem

if

is assumed to be a real number.
| Out[18]= |  |
If you say that a variable satisfies an inequality,
Mathematica will automatically assume that it is real.
| Out[19]= |  |
By using
Simplify,
FullSimplify, and
FunctionExpand with assumptions you can access many of
Mathematica's vast collection of mathematical facts.
This uses the periodicity of the tangent function.
| Out[20]= |  |
The assumption
Integers implies that
k must be even.
| Out[21]= |  |
Mathematica knows that

for positive

.
| Out[22]= |  |
| Out[23]= |  |
Mathematica knows about discrete mathematics and number theory as well as continuous mathematics.
This uses Wilson's theorem to simplify the result.
| Out[24]= |  |
This uses the multiplicative property of the Euler phi function.
| Out[25]= |  |
In something like
Simplify
or
Refine
you explicitly give the assumptions you want to use. But sometimes you may want to specify one set of assumptions to use in a whole collection of operations. You can do this by using
Assuming.
| Assuming[assum,expr] | use assumptions assum in the evaluation of expr |
| $Assumptions | the default assumptions to use |
Specifying assumptions with larger scopes.
This tells
Simplify to use the default assumption
x>0.
| Out[26]= |  |
This combines the two assumptions given.
| Out[27]= |  |
Functions like
Simplify and
Refine take the option
Assumptions, which specifies what default assumptions they should use. By default, the setting for this option is
Assumptions:>$Assumptions. The way
Assuming then works is to assign a local value to
$Assumptions, much as in
Block.
In addition to
Simplify and
Refine, a number of other functions take
Assumptions options, and thus can have assumptions specified for them by
Assuming. Examples are
FunctionExpand,
Integrate,
Limit,
Series,
LaplaceTransform.
The assumption is automatically used in
Integrate.
| Out[28]= |  |