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SOLUTIONS
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BUILT-IN MATHEMATICA SYMBOL
PadLeft
PadLeft[list, n]
makes a list of length n by padding list with zeros on the left.
PadLeft[list, n, x]
pads by repeating the element x.
PadLeft[list, n, {x1, x2, ...}]
pads by cyclically repeating the elements
.
PadLeft[list, n, padding, m]
leaves a margin of m elements of padding on the right.
PadLeft[list, {n1, n2, ...}]
makes a nested list with length
at level i.
PadLeft[list]
pads a ragged array list with zeros to make it full.
DetailsDetails
- PadLeft[list, n, ...] always returns a list of length n, except in some special cases where padding is
. - With padding
, cyclic repetitions of the
are effectively laid down and then the list is superimposed on top of them, with the last element of the list lying on an occurrence of
. » - PadLeft[list, n, padding, -m] truncates the last m elements of list.
- A margin of Round[(n-Length[list])/2] effectively centers list.
- PadLeft[list, n, list] effectively treats list as cyclic.
- PadLeft[list, n, {xlist}] can be used to repeat an individual element that is itself a list.
- PadLeft[{}, n, {x1, x2, ...}] repeats the sequence of
as many times as fit in a list of length n. - PadLeft[list, {n1, n2, ...}] creates a full array with dimensions
even if list is ragged. » - PadLeft[list, Automatic, x] pads with x to make a full array.
- Negative
specify to pad on the right. - PadLeft[list, {n1, n2}, {{x11, x12, ...}, {x21, ...}, ...}] pads by repeating the block of
. - PadLeft[list, {n1, n2, ...}, list] effectively treats list as cyclic in every dimension.
- PadLeft[list, {n1, n2, ...}, padding, {m1, m2, ...}] uses margin
at level i. - The object list need not have head List.
- PadLeft can be used on SparseArray objects.
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