WOLFRAM SYSTEMMODELER

SimpleCooling

Simple cooling circuit

Diagram

Wolfram Language

In[1]:=
SystemModel["Modelica.Thermal.FluidHeatFlow.Examples.SimpleCooling"]
Out[1]:=

Information

This information is part of the Modelica Standard Library maintained by the Modelica Association.

1st test example: SimpleCooling

A prescribed heat source dissipates its heat through a thermal conductor to a coolant flow. The coolant flow is taken from an ambient and driven by a pump with prescribed mass flow.
Results:
output explanation formula actual steady-state value
dTSource Source over Ambient dtCoolant + dtToPipe 20 K
dTtoPipe Source over Coolant Losses / ThermalConductor.G 10 K
dTCoolant Coolant's temperature increase Losses * cp * massFlow 10 K

Parameters (2)

medium

Value: Modelica.Thermal.FluidHeatFlow.Media.Medium()

Type: Medium

Description: Cooling medium

TAmb

Value: 293.15

Type: Temperature (K)

Description: Ambient temperature

Outputs (3)

dTSource

Default Value: prescribedHeatFlow.port.T - TAmb

Type: TemperatureDifference (K)

Description: Source over Ambient

dTtoPipe

Default Value: prescribedHeatFlow.port.T - pipe.T_q

Type: TemperatureDifference (K)

Description: Source over Coolant

dTCoolant

Default Value: pipe.dT

Type: TemperatureDifference (K)

Description: Coolant's temperature increase

Components (11)

medium

Type: Medium

Description: Cooling medium

ambient1

Type: Ambient

pump

Type: VolumeFlow

pipe

Type: Pipe

ambient2

Type: Ambient

heatCapacitor

Type: HeatCapacitor

prescribedHeatFlow

Type: PrescribedHeatFlow

volumeFlow

Type: Constant

heatFlow

Type: Constant

convection

Type: Convection

thermalConductance

Type: Constant