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SOLUTIONS
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BUILT-IN MATHEMATICA SYMBOL
BinCounts
BinCounts[{x1, x2, ...}]
counts the number of elements
whose values lie in successive integer bins.
BinCounts[{x1, x2, ...}, dx]
counts the number of elements
whose values lie in successive bins of width dx.
BinCounts[{x1, x2, ...}, {xmin, xmax, dx}]
counts the number of
in successive bins of width dx from
to
.
BinCounts[{x1, x2, ...}, {{b1, b2, ...}}]
counts the number of
in the intervals
,
, ....
BinCounts[{{x1, y1, ...}, {x2, y2, ...}, ...}, xbins, ybins, ...]
gives an array of counts where the first index corresponds to x bins, the second to y, and so on.
DetailsDetails
- BinCounts drops elements whose values do not correspond to real numbers.
- BinCounts[data, dx] takes the bin boundaries to be integer multiples of dx, with the first bin starting at Ceiling[Min[data]-dx, dx] and the last bin ending at Floor[Max[data]+dx, dx].
- BinCounts[data] is equivalent to BinCounts[data, 1].
- BinCounts[data, {xmin, xmax}] is equivalent to BinCounts[data, {xmin, xmax, 1}].
- In BinCounts[data, {xmin, xmax, dx}], elements are counted in bin i when their values satisfy
. - In the form BinCounts[data, {{b1, b2, ...}}], the
at each end can be -Infinity and +Infinity. - If the
do not form an increasing sequence, they are automatically sorted by BinCounts. - In BinCounts[data, {{b1, b2, ...}}], elements are counted in bin i when their values satisfy
. - If data consists of length-n sublists, then n bin specifications must be given, and BinCounts[data, ...] yields an array of depth n.
- BinCounts works with SparseArray objects.
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