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SequenceCases[list,patt]

给出 list 中匹配 patt 序列模式的子表的列表.

SequenceCases[list,pattrhs]

给出对应匹配 patt 子表的 rhs 的值.

SequenceCases[list,patt,n]

只包括前 n 次匹配.

更多信息和选项
Details and Options Details and Options
范例  
基本范例  
范围  
选项  
Overlaps  
属性和关系  
参见
相关指南
相关链接
历史
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SequenceCases

SequenceCases[list,patt]

给出 list 中匹配 patt 序列模式的子表的列表.

SequenceCases[list,pattrhs]

给出对应匹配 patt 子表的 rhs 的值.

SequenceCases[list,patt,n]

只包括前 n 次匹配.

更多信息和选项

  • 在 SequenceCases[list,patt] 中，patt 可以是一个标头为 List 的表达式，包括诸如 PatternSequence、Repeated (..)、Blank (_)、BlankSequence (__) 的模式构造.
  • 模式 patt 也可以是匹配某列表但自身没有标头 List 的模式.
  • 默认选项设置 OverlapsFalse 下，SequenceCases 只包括互相不重叠的子表. 若设定为 OverlapsTrue，则包括互相重叠的子表.
  • 在 Overlaps->All 设置下，则包括匹配相同模式的多个子表. 在 Overlaps->True 设置下，只包括在某个指定位置首先有该匹配的子列表.

范例

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基本范例  (2)

求出匹配某模式的子表：

Wolfram Language code: SequenceCases[{a, b, x, x, a, c}, {a, _}]

对每一个匹配做替换：

Wolfram Language code: SequenceCases[{a, b, x, x, a, c}, {a, x_} :> f[x]]

算出 b 中所有连续序列的长度：

Wolfram Language code: SequenceCases[{a, b, b, a, b, b, b}, {p : Repeated[b]} :> Length[{p}]]

范围  (3)

求出匹配某模式的元素序列：

Wolfram Language code: SequenceCases[Range[1000], {_ ? PrimeQ, _, _ ? PrimeQ}]

求出列表中所有相互重叠部分的序列：

Wolfram Language code: SequenceCases[Range[10], list_ /; Length[list] == 6, Overlaps -> True]

基于所得结果计算一个函数：

Wolfram Language code: SequenceCases[Range[1000], {a_ ? PrimeQ, b_, c_ ? PrimeQ} :> Row[Superscript@@@FactorInteger[b]]]

选项  (2)

Overlaps  (2)

允许重叠：

Wolfram Language code: SequenceCases[{a, b, a, b, a, b, a, b}, {a, b, a, b}, Overlaps -> True]

不允许重叠：

Wolfram Language code: SequenceCases[{a, b, a, b, a, b, a, b}, {a, b, a, b}, Overlaps -> False]

在不同位置开始允许重叠：

Wolfram Language code: SequenceCases[{a, b, c, d}, {__}, Overlaps -> True]

不允许重叠：

Wolfram Language code: SequenceCases[{a, b, c, d}, {__}, Overlaps -> False]

允许所有重叠：

Wolfram Language code: SequenceCases[{a, b, c, d}, {__}, Overlaps -> All]

属性和关系  (3)

求出某序列的位置：

Wolfram Language code: SequencePosition[{a, b, 1, 2, c, d, 3, 4}, {__Symbol}, Overlaps -> False]

求出实际的序列：

Wolfram Language code: SequenceCases[{a, b, 1, 2, c, d, 3, 4}, {__Symbol}, Overlaps -> False]

计算序列的数量：

Wolfram Language code: SequenceCount[{a, b, 1, 2, c, d, 3, 4}, {__Symbol}, Overlaps -> False]

用表达式替代序列：

Wolfram Language code: SequenceReplace[{a, b, 1, 2, c, d, 3, 4}, {__Symbol} -> "X"]

对于字符列表来说，SequenceCases 类似于 StringCases：

Wolfram Language code: text = "On 31/12/2003 we left, and on 5/3/2004 we came back";
Wolfram Language code: SequenceCases[Characters[text], {_ ? LetterQ..}]
Wolfram Language code: StringCases[text, LetterCharacter..]

SubsetCases 匹配元素以任意顺序排列的序列：

Wolfram Language code: SubsetCases[{1, a, 2, 3, a, b, c}, {a, _Integer}]

SequenceCases 只按指定顺序匹配序列：

Wolfram Language code: SequenceCases[{1, a, 2, 3, a, b, c}, {a, _Integer}]
Wolfram Research (2015)，SequenceCases，Wolfram 语言函数，https://reference.wolfram.com/language/ref/SequenceCases.html.

文本

Wolfram Research (2015)，SequenceCases，Wolfram 语言函数，https://reference.wolfram.com/language/ref/SequenceCases.html.

CMS

Wolfram 语言. 2015. "SequenceCases." Wolfram 语言与系统参考资料中心. Wolfram Research. https://reference.wolfram.com/language/ref/SequenceCases.html.

APA

Wolfram 语言. (2015). SequenceCases. Wolfram 语言与系统参考资料中心. 追溯自 https://reference.wolfram.com/language/ref/SequenceCases.html 年

BibTeX

@misc{reference.wolfram_2026_sequencecases, author="Wolfram Research", title="{SequenceCases}", year="2015", howpublished="\url{https://reference.wolfram.com/language/ref/SequenceCases.html}", note=[Accessed: 02-November-2026]}

BibLaTeX

@online{reference.wolfram_2026_sequencecases, organization={Wolfram Research}, title={SequenceCases}, year={2015}, url={https://reference.wolfram.com/language/ref/SequenceCases.html}, note=[Accessed: 02-November-2026]}