给出代数数 a 的范数.
AlgebraicNumberNorm
给出代数数 a 的范数.
更多信息和选项
- a 的范数定义为其极小多项式根的积.
- AlgebraicNumberNorm[a,Extension->θ] 在域
内求出 a 的范数.
范例
打开所有单元 关闭所有单元基本范例 (1)
范围 (4)
AlgebraicNumberNorm[2]AlgebraicNumberNorm[-2 / 3]AlgebraicNumberNorm[1 / Sqrt[Sqrt[2] + 3]]Root 和 AlgebraicNumber 对象:
AlgebraicNumberNorm[Root[-1 + #1 + #1 ^ 2 + #1 ^ 3 + #1 ^ 4 & , 1]]AlgebraicNumberNorm[AlgebraicNumber[Sqrt[2] I, {1, 2}]]AlgebraicNumberNorm 自动线性作用于列表:
AlgebraicNumberNorm[{2Sqrt[2], E ^ (Pi * I / 8), 1 + I}]选项 (1)
应用 (1)
AlgebraicNumberNorm[9 + Sqrt[10]]由于 AlgebraicNumberNorm 为积性,具有素范数说明其初始数为素数:
PrimeQ[%]属性和关系 (3)
AlgebraicNumberNorm 为积性:
AlgebraicNumberNorm[{2, Sqrt[5]}, Extension -> Sqrt[5]]AlgebraicNumberNorm[2 Sqrt[5], Extension -> Sqrt[5]]AlgebraicNumberNorm /@ NumberFieldFundamentalUnits[Sqrt[2] + Sqrt[3]]AlgebraicNumberNorm /@ NumberFieldFundamentalUnits[Root[16 - 20 #1^2 + #1^4&, 4]]e = ToNumberField[{Sqrt[3], Sqrt[-5]}, All][[1, 1]]AlgebraicNumberNorm[Sqrt[3] + Sqrt[-5], Extension -> e]技术笔记
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- 代数数域
文本
Wolfram Research (2007),AlgebraicNumberNorm,Wolfram 语言函数,https://reference.wolfram.com/language/ref/AlgebraicNumberNorm.html.
CMS
Wolfram 语言. 2007. "AlgebraicNumberNorm." Wolfram 语言与系统参考资料中心. Wolfram Research. https://reference.wolfram.com/language/ref/AlgebraicNumberNorm.html.
APA
Wolfram 语言. (2007). AlgebraicNumberNorm. Wolfram 语言与系统参考资料中心. 追溯自 https://reference.wolfram.com/language/ref/AlgebraicNumberNorm.html 年
BibTeX
@misc{reference.wolfram_2026_algebraicnumbernorm, author="Wolfram Research", title="{AlgebraicNumberNorm}", year="2007", howpublished="\url{https://reference.wolfram.com/language/ref/AlgebraicNumberNorm.html}", note=[Accessed: 17-August-2026]}
BibLaTeX
@online{reference.wolfram_2026_algebraicnumbernorm, organization={Wolfram Research}, title={AlgebraicNumberNorm}, year={2007}, url={https://reference.wolfram.com/language/ref/AlgebraicNumberNorm.html}, note=[Accessed: 17-August-2026]}