# Wronskian

Wronskian[{y1,y2,},x]

gives the Wronskian determinant for the functions y1,y2, depending on x.

Wronskian[eqn,y,x]

gives the Wronskian determinant for the basis of the solutions of the linear differential equation eqn with dependent variable y and independent variable x.

Wronskian[eqns,{y1,y2,},x]

gives the Wronskian determinant for the system of linear differential equations eqns.

# Details and Options • The Wronskian determinant is defined as Det[Table[D[yi,{x,j}],{i,m},{j,0,m-1}]].
• If the functions y1,y2, are linearly dependent, the Wronskian vanishes everywhere.

# Examples

open allclose all

## Basic Examples(3)

These functions are linearly independent:

These functions are dependent:

The Wronskian for a linear equation:

Except for a constant, the result is the same as for the explicit solution:

## Scope(9)

### Functions(6)

Polynomials:

The last element can be expressed as a linear combination of the previous ones:

Rational functions:

Exponentials and exponential polynomials:

Trigonometric functions:

Special polynomials:

Other special functions:

### Differential Equations(3)

Constant coefficient linear equation:

The Wronskian for a differential equation is usually simpler than for its solution:

Polynomial coefficient linear equation:

The corresponding Wronskian from the general solution:

Special function coefficients:

## Applications(2)

Variation of parameters formula for forced second-order differential equations:

Verify that the components of the general solution for an ODE are linearly independent:

## Properties & Relations(5)

Wronskian is equivalent to a determinant:

Wronskian detects linear dependence:

Casoratian performs linear dependence for sequences of a discrete argument:

Use Orthogonalize to generate a set of linearly independent functions:

Express a function in terms of the basis:

The last component is linearly dependent on the previous ones:

Use Reduce to express polynomials and rational functions in terms of each other:

## Neat Examples(1)

The differential equation for Kelvin functions:

Compare to the general solution: